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An Austin volleyball player bumps a 5 kg ball into the air. It reaches a height of 2.8 meters. How fast was the ball going as it got bumped into the air?

O 137.2 m/s
O 7.4 m/s
O 19.6 m/s
O 14 m/s

User Vivian
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1 Answer

3 votes

Answer:

v = 7.4 m/s

Step-by-step explanation:

Given that,

Mass if a volleyball, m = 5 kg

The ball reaches a height of 2.8 m

We need to find how fast the ball is going as it bumped into the air. Ket the velocity is v. Using the conservation of energy to find it as follows :


mgh=(1)/(2)mv^2\\\\v=√(2gh) \\\\v=√(2* 9.8* 2.8) \\\\=7.4\ m/s

So, the required speed is 7.4 m/s. Hence, the correct option is (b).

User Bupereira
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7.5k points