28.3k views
0 votes
Graph the inequality on the axes below.

2x + y > -8
Y
10
9
8
6
5
-9
-S
- -
5
--
3 -2
3
+
2
3
+
5
9 10

Graph the inequality on the axes below. 2x + y > -8 Y 10 9 8 6 5 -9 -S - - 5 -- 3 -2 3 + 2 3 + 5 9 10-example-1
User Shally
by
4.6k points

1 Answer

3 votes

The first step is to graph the line 2x + y = -8. To do this, we can graph the x and y-intercepts. Letting x = 0, we get y = -8, so the y-intercept is -8. Letting y = 0, we get 2x = -8, so x = -4.

Graph the line between the points (-4, 0) and (0, -8). The line should be dotted, because this is a strict inequality (the points on the line are not part of the solution).

The next step is to substitute a point - I like to use (0,0): when x and y are equal to zero, we have 2(0)+0>-8, which is true. Therefore, the right side of the graph (which contains the point (0,0)) should be shaded. Note: If the inequality was not true, you would want to shade the opposite side of the graph.

Graph the inequality on the axes below. 2x + y > -8 Y 10 9 8 6 5 -9 -S - - 5 -- 3 -2 3 + 2 3 + 5 9 10-example-1
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.