Answer:
5 3/4yd²
Explanation:
Area of the pen = length × width
Given
Length = 3 5/6 yds
Width = 1 1/2 yards
Area = 3 5/6 × 1 1/2
Area = 23/6 × 3/2
Area= 23/4
Area = 5 3/4yd²
Hence t required area is 5 3/4yd²
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