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Write the equation of the circle centered at (-6, - 10) with radius 18.

User Aroc
by
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2 Answers

9 votes

Answer:


(x+6)^2 +(y+10)^2 = 324

Explanation:


\underline{\textbf{Equation of circle(Standard form)}}\\\\~~~~~~~~~~~~~~~~~~~~(x-h)^2 + (y-k)^2 =r^2\\\\\text{Where,}\\\\(h,k) = \text{Center of the circle.}\\\\r = \text{Radius of the circle.}\\


\underline{\textbf{Solution:}}\\\\\text{Given that,}\\\\\text{Center of the circle,}~ (h,k) = (-6,-10)\\\\\text{Radius of the circle,}~ r = 18~ \text{units.}\\\\\text{From the given data, the equation of the circle is,}\\\\~~~~~~~~~~~~~~~~~~~~(x-h)^2 +(y-k)^2 = r^2\\\\~~~~~~~~~~~\implies (x-(-6))^2+ (y-(-10))^2 = 18^2\\\\~~~~~~~~~~~\implies \boxed{(x+6)^2 +(y+10)^2 = 324}

User Barnack
by
8.2k points
9 votes

Answer:

(x + 6)² + (y + 10)² = 324

Explanation:

Formula:

The equation of a circle centered at (a , b) with radius r is :

(x − a)² + (y − b)² = r²

……………………………………

then

the equation of the circle centered at (-6, - 10) with radius 18 is :

(x − (-6))² + (y − (-10))² = 18²

⇔ (x + 6)² + (y + 10)² = 324

⇔ x² + 12x + y² + 20y - 188 = 0

User Advanced Customer
by
9.0k points

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