153k views
4 votes
. An object is launched straight up into the air. It is launched from a height

of H feet off the ground. Its height H, in feet, at t seconds is given by the
equation H = -8t^2 + 40t + 18. Find all times t that the object is at a height
of 50 feet off the ground.

User AndreasRu
by
7.2k points

1 Answer

4 votes

Answer:

H=24

Explanation:

User Jms Bnd
by
6.9k points