Question

hi can i please have some help w/ these! i have my exam tomorrow!!! factoring algebra 2! worth 35 points!

Answer 1

11.
`4x^(3)-10x^(2)+6x`

Take out 2x ( greatest common factor )

`2x(2x^(2)-5x+3)`

Factor

`2x(2x^(2) -2x-3x+3)`

`2x(x-1)-3(x-1)=(2x-3)(x-1)`

Don't forget about the 2x we took out earlier

Solution to 11:
`2x(2x-3)(x-1)`

12.
`16x^(2) -25y^(2)`

This is the difference of squares, so let's use the formula...

`a^(2)-b^(2)=(a-b)(a+b)`

if,
`a=16x^(2)` and
`b=25y^(2)`

then, the Solution to 12 is:

`(4x-5y)(4x+5y)`

13.
`3x^3-24`

First of all, you must find the greatest common factor because there isn't anything else you can do.

`3(x^3-8)`

Now you can see the difference of cubes...

`a^3-b^3=(a-b)(a^2+ab+b^2)`

so, the Solution to 13 is:

`3(x^3-8)= 3(x-2)(x^2+2x+4)`