Question

A JFET has a drain current of 5mA. If IDSS = 10mA and VGS ( off )= -6 v. find The Value Of

( 1 ) VGS
( 2 ) VP


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Answer 1

`\underline {\huge \boxed{ \sf \color{skyblue}Answer : }}`

Given :

`\tt \large {\color{purple} ↬ } \: \: \: \: \: I_(D) = 5mA`

`\: \:`

`\tt \large {\color{purple} ↬ } \: \: \: \: \: I_(DSS) = 10mA`

`\: \:`

`\tt \large {\color{purple} ↬ } \: \: \: \: \: V_(GS(off)) = -6V`

`\: \:`

`\tt \large {\color{purple} ↬ } \: \: \: \: \: V_(GS) = {?}`

`\: \: \:`

Let's Slove :

• 
  `\tt \large I_(D) = I_((DSS)) (1 - \frac {V_(GS)}{V_(GS(off))} )^(2)`

`\: \: \:`

• 
  `\tt \large \: V_(GS) = (1 - \frac{ √(I_D) }{ \sqrt{I_(DSS)} } ) * V_(GS(off))`

`\: \: \:`

• 
  `\tt \large \: V_(GS) = (1 - ( √(5m) )/( √(10m) ) ) * { - 6}`

`\: \:`

• 
  `\underline \color{red} {\tt \large \boxed {\tt V_(GS) = 1.75 ✓}}`