Question

A long spring is strecthed by 2cm and it's potential energy is v. If the spring is stretched by 10 cm it's potential energy will be ?​

Answer 1

Hey There!

Let's solve....

`v = (1)/(2) k{x}^(2) \\ \\ ( v_(1) )/( v_(2) ) = (( x_(1) )/( x_(2))) ^(2) \\ \\ (v)/( v_(2) ) =( \frac{ \cancel{2}}{ \cancel{10 }}) ^(2) \\ \\ = (1)/(25) \\ \\ v_(2) = 25v_(1) \\ \\ = 25v`

I hope it is helpful to you...

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