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Solve 6x^2 - 12x + 24 = 0 by completing the square

1 Answer

3 votes

Answer:
\quad x=1+√(3)i,\:x=1-√(3)i

Step-by-step explanation:
x_(1,\:2)=(-\left(-12\right)\pm √(\left(-12\right)^2-4\cdot \:6\cdot \:24))/(2\cdot \:6)


  • x_(1,\:2)=(-\left(-12\right)\pm \:12√(3)i)/(2\cdot \:6)

  • x_1=(-\left(-12\right)+12√(3)i)/(2\cdot \:6),\:x_2=(-\left(-12\right)-12√(3)i)/(2\cdot \:6)

  • x=1+√(3)i,\:x=1-√(3)i

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