Answer:
The distance is
Step-by-step explanation:
From the question we are told that
The period of the moon
![T = 1.2 days = 1.2 * 24 * 3600 = 103680 \ s](https://img.qammunity.org/2021/formulas/physics/college/6uum16urhabmxd1mxn3o6i70yomx86n2v8.png)
The mass of the planet is
![m_p = 9.38*10^(24) kg](https://img.qammunity.org/2021/formulas/physics/college/f0kjt2khj3yyb5s9oof7k8i1sfb5jc2il3.png)
Generally the period of the moon is mathematically represented as
![T = 2 * \pi * \sqrt{ (r^3 )/( G * m_p ) }](https://img.qammunity.org/2021/formulas/physics/college/wgxcq1pz47fuvswshiq2zosmvlbyeosvxh.png)
Here G is the gravitational constant with value
![G = 6.67 *10^(-11) \ N \cdot m^2/kg^2](https://img.qammunity.org/2021/formulas/physics/college/y05lem9xgpzpqhohexanh5zkq6c64bwi75.png)
=>
![T = 2 * \pi * \sqrt{ (r^3 )/( G * m_p ) }](https://img.qammunity.org/2021/formulas/physics/college/wgxcq1pz47fuvswshiq2zosmvlbyeosvxh.png)
=>
![103680 = 2 * 3.142 * \sqrt{ (r^3 )/( 6.67*10^(-11) * 9.38*10^(24) ) }](https://img.qammunity.org/2021/formulas/physics/college/zrw7tk72a1ymzz1luo6ns87a6e59ewabfm.png)
=>
![272218492.31 = (r^3)/( 6.67 *10^(-11) * 9.38*10^(24))](https://img.qammunity.org/2021/formulas/physics/college/y9k0cvxax24rbmly9k6effxu92flaufx7u.png)
=>
j
=>