Question

What would have to be the self-inductance of a solenoid for it to store 10.2J of energy when a 1.20A current runs through it?

Answer 1

14.17H

Step-by-step explanation:

Energy stored in an inductor is expressed as;

E = 1/2LI²

L is the inductance of the inductor

I is the current flowing through the inductor

Given

E = 10.2J

I = 1.20

Required

Inductance L

Substitute the given parameters into the formula;

10.2 = 1/2L(1.2)²

10.2 = 1/2*1.44L

10.2 = 0.72L

L = 10.2/0.72

L = 14.17H

Hence the self inductance of the solenoid is 14.17H