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If the magnitude of the electric field of an electromagnetic wave is 3x10^3 V/m, what is the the magntude of the magnetic field?

a. 1.1 x 10^-12 T
b. 9 x 10^11 T
c. 10^5 T
d. 10^-5 T
e. 3 x 10^3 T

1 Answer

2 votes

Answer:

The value of the magnetic field is
B = 1.0*10^(-5) \ T

The correct option is d

Step-by-step explanation:

From the question we are told that

The magnitude of the electric field is
E = 3*10^(3) \ V/m

Generally the magnitude of the magnetic field is mathematically represented as


B = (E)/(c)

Here c is the speed of light
c = 3.0*10^(8) \ m/s

=>
B = (E)/(c)

=>
B = (3.0*10^(3))/( 3.0*10^(8))

=>
B = 1.0*10^(-5) \ T

User Ibraheem Ahmed
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