Question

Margaret wants to go for a swim, and decides to jump in using the diving board that measures 3-m long.

She initially leaps with a velocity of 8.0 m/s at an angle of 80° to the horizontal.
What are the horizontal and vertical components of her velocity?

please help if you can!

Answer 1

The horizontal component of her velocity is approximately 1.389 m/s

The vertical component of her velocity is approximately 7.878 m/s

Step-by-step explanation:

The given question parameters are;

The initial velocity with which Margaret leaps, v = 8.0 m/s

The angle to the horizontal with which she jumps, θ = 80° to the horizontal

The horizontal component of her velocity, vₓ = v × cos(θ)

∴ vₓ = 8.0 × cos(80°) ≈ 1.389

The horizontal component of her velocity, vₓ ≈ 1.389 m/s

The vertical component of her velocity,
`v_y` = v × sin(θ)

∴
`v_y` = 8.0 × sin(80°) ≈ 7.878

The vertical component of her velocity,
`v_y` ≈ 7.878 m/s.