Question

An ideal heat engine absorbs 97.2 kJ of heat and exhausts 83.8 kJ of heat in each cycle. What is the efficiency of the engine?

Answer 1

13.7%

Step-by-step explanation:

Given that,

Heat absorbed by the engine = 97.2 kJ

Heat exhausted by the engine in each cycle = 83.8 kJ

We need to find the efficiency of the engine. It is calculated by the formula.

`\eta=1-(Q_e)/(Q_a)\\\\=1-(83.8)/(97.2)\\\\=0.137\\\\=13.7\%`

so, the efficiency of heat engine is 13.7%.