Question

How much heat is absorbed by 3 kg honey baked ham as energy from the oven causes its temperature to change from 10°C to 60°C? (Specific heat capacity of ham 3287 cal/kgºC)?

Answer 1

The honey-baked ham absorbs approximately 492,900 calories of heat energy from the oven.

Step-by-step explanation:

To calculate the amount of heat absorbed by the honey-baked ham, we can use the formula: Q = mcΔT, where Q is the heat absorbed, m is the mass of the ham, c is the specific heat capacity of the ham, and ΔT is the temperature change.

Given that the mass of the ham is 3 kg the specific heat capacity is 3287 cal/kg°C, and the temperature change is from 10°C to 60°C, we can substitute the values into the formula.

Q = (3 kg)(3287 cal/kg°C)(60°C - 10°C) = 3 x 3287 x 50 = 492,900 cal

Therefore, the honey-baked ham absorbs approximately 492,900 calories of heat energy from the oven.

Answer 2

The answer is 493.05kJ

Step-by-step explanation:

given

mass m= 3kg

t1= 10°C

t2= 60°C

Specific heat capacity of ham =3287 cal/kgºC

Required,

The quantity of heat, Q

Step two:

the formula is

Q= mcΔT

substitute

Q= 3*3287(60-10)

Q=9861*50

Q=493050 J

Q= 493.05kJ