Question

A 1 kg puck sliding on a horizontal shuffleboard court is slowed to rest by 1 point

a frictional force of 3 N. What is the coefficient of kinetic friction between
the puck and the surface of the shuffleboard court? *
O A. 0.25
O B.0.5
O c.0.15
D. .31

Answer 1

miu = 0.31

Step-by-step explanation:

The friction force is defined as the product of the normal force by the coefficient of friction.

`f=miu*N`

where:

f = friction force = 3 [N]

miu = friction coefficient

N = normal force [N]

The normal force on a horizontal surface can be calculated by means of the product of mass by gravity.

where:

m = mass = 1 [kg]

g = gravity acceleration = 9.81 [m/s²]

`N=m*g\\N=1*9.81`

`N= 9,81 [N]`

Now replacing in the equation above, we can find the friction coefficient.

`miu=3/9.81\\miu = 0.31`