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A jet aircraft is traveling at 262 m/s in hor-

izontal flight. The engine takes in air at a

rate of 85.9 kg/s and burns fuel at a rate of

3.92 kg/s. The exhaust gases are ejected at

921 m/s relative to the aircraft.

Find the thrust of the jet engine.

User Demental
by
3.9k points

1 Answer

3 votes

Solution :

Speed of the air craft,
$S_a$ = 262 m/s

Fuel burns at the rate of,
$S_b$ = 3.92 kg/s

Rate at which the engine takes in air,
$S_(air)$ = 85.9 kg/s

Speed of the exhaust gas that are ejected relative to the aircraft,
$S_(exh)$ =921 m/s

Therefore, the upward thrust of the jet engine is given by


$F=S_(air)(S_(exh)-S_a)+(S_b * S_(exh))$

F = 85.9(921 - 262) + (3.92 x 921)

= 4862635.79 + 3610.32

=
$4.8 * 10^6 \ N$

Therefore thrust of the jet engine is
$4.8 * 10^6 \ N$.

User Michael Gaskill
by
5.1k points