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What force must be applied to the end of a rod along the x-axis of length 2.25 m in order to produce a torque on the rod about the origin of 11 z-hat N·m? Choose among the available options below. x,y,z,-z

User Srhise
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5.0k points

1 Answer

1 vote

Answer:

4.9N approx.

Step-by-step explanation:

Step one:

given data

length of rod r= 2.25m

Required torque = 11 Nm

Required

The force needed to produce a torque of 11Nm

Step two:

"By definition, Torque is the twisting force that tends to cause rotation.

The point where the object rotates is known as the axis of rotation."

Mathematically,


\tau = rF\sin\theta


\tau = torque

r = radius

F = force


\theta = angle between F and the lever arm

in this case is zero


\tau = rF\\\\F=\tau/r

substituting we have

F=11/2.25

F=4.88N

F=4.9N approx.

User Kyriaki
by
5.2k points