Question

A cylinder, with a piston pressing down with a constant pressure, is filled with 2.10 moles of a gas (n1), and its volume is 46.0 L (V1). If 0.700 mole of gas leak out, and the pressure and temperature remain the same, what is the final volume of the gas inside the cylinder?

Answer 1

The volume is
`V_2 =15.33 \ L`

Step-by-step explanation:

From the question we are told that

The number of moles of the gas is
`n_1 = 2.10 \ moles`

The volume of the gas is
`V = 46.0 \ L`

The of moles of the gas that leaked is
`n_2 = 0.700 \ mol`

Generally from the ideal gas law

`PV = nRT`

Generally at constant pressure and temperature

`(V)/(n) = constant`

So
`(V_1 )/(n_1) = (V_2 )/(n_2)`

=>
`V_2 = ( V_1 * n_2 )/( n_1)`

=>
`V_2 = ( 46.0 * 0.700 )/( 2.10 )`

=>
`V_2 =15.33 \ L`