Question

If in the reaction below 32 grams of C2H6 produces 44 grams of CO2, what is the % yield? 2C2H6 + 7O2 = 4CO2 + 6H2O

imagine the = is an arrow

Answer 1

Answer: 46.875%

the moles of C2H6 is 32/(12.2+6) = 16/15 (mol)

the moles of CO2 is 44/(12 + 16.2) = 1 (mol)

have:

2C2H6 + 7O2 ⇒ 4CO2 + 6H2O

0,5 <= 1

=> C2H6 reacts 0.5 mol

=> H =
`(0.5)/((16)/(15) ).100=46.875`%

Step-by-step explanation: