Question

A compared of magnesium nitric contains 72% of magnesium and 28% of nitrogen. what is the empirical formula of magnesium nitric.

and the answer is Mg 3 N 2

how to do the solution. ​

Answer 1

The empirical formula : Mg₃N₂

Further explanation

The empirical formula is the smallest comparison of atoms of compound =mole ratio of the components

The principle of determining empirical formula

• Determine the mass ratio of the constituent elements of the compound.

• Determine the mole ratio by dividing the percentage by the atomic mass

The empirical formula :

mol ratio Mg : N ⇒

`\tt =(72)/(24~g/mol)/ (28)/(14~g/mol)\\\\=3/ 2\rightarrow Mg_3N_2`