Question

You have 3.00 L of a 3.12 M solution of NaCl(aq) called solution A. You also have 2.00 L of a 2.00 M solution of AgNO3(aq) called solution B. You mix these solutions together, making solution C.

Calculate the concentration (in M) of Ag+ ions in solution C.

Answer 1

`M=0.8M`

Step-by-step explanation:

Hello!

In this case, since the presence of silver ions is in AgNO3 only, we can compute their moles by using the volume and concentration of the corresponding salt:

`n_(Ag^+)=2.00L*2.00(mol)/(L)=4molAg^+`

Next, since the total volume of solution C is 5.00 L, the required concentration of silver ions turn out:

`M=(4.00mol)/(5L) =0.8M`

Best regards!