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Given the equation f(t) = 225(1.23)

What is the rate of growth or decay?
%
What is the initial value?

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Answer:

This function doesn't make sense, unless you make it f(t)=225(1.23)^x. I will assume that you forgot to add the x squared. The rate of decay is 23%. Since the base is between 1 and 0, it is an exponential decay and you'll need to subtract the r-value with 1. (If it were an exponential growth, you would have to add 1.) The initial value or the a-value is 225.

User Himanshu Mori
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