Question

Write the equation of a parellel to the given line that goes through the given point y=8x+3 (2,4)

Answer 1

The equation of a parallel to the given line that goes through the given point (2, 4) is:

`y=8x-12`

Explanation:

Given the equation

`y=8x+3`

comparing the equation with the slope-intercept form

`y=mx+b`

Here,

• m is the slope

• y is the intercept

so the slope of the line is m = 8.

We know that the slopes of parallel lines are equal.

so, the slope of the perpendicular line will be = 8

Therefore, the equation of a parallel to the given line that goes through the given point (2, 4) is:

`y-y_1=m\left(x-x_1\right)`

`y-4 = 8 (x-2)`

`y-4 = 8x-16`

`y = 8x-16+4`

`y=8x-12`