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F = xi+yj+2zk and σ is the portion of the cone z=x2+y2−−−−−−√ between the planes z=4 and z=5 oriented with normal vectors pointing upwards. Find the flux of the flow field F across σ
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F = xi+yj+2zk and σ is the portion of the cone z=x2+y2−−−−−−√ between the planes z=4 and z=5 oriented with normal vectors pointing upwards. Find the flux of the flow field F across σ

User Stckvrw
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User Matt McClellan
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