Question

A mover slides a refrigerator weighing 650 N at a constant velocity across the floor a distance of 8.1 m. The force of friction between the refrigerator and the floor is 230 N. How much work has been performed by the mover on the refrigerator

Answer 1

The magnitude of the work performed by the mover is 1863 J.

Step-by-step explanation:

The work can be found using the following equation:

`W = F*d`

Where:

F: is the force

d: is the displacement = 8.1 m

First, we need to find the net force in the horizontal direction, as follows:

`\Sigma F_(x) = ma = 0`

a = 0 since the mover slides a refrigerator at a constant velocity.

`F_(x) = F_(f) = -230 N`

`F_(f)`: is the friction force.

Then, the work is:

`W = F*d = -230 N*8.1 m = -1863 J`

Therefore, the magnitude of the work performed by the mover is 1863 J.

I hope it helps you!