Question

Two waves were analyzed with some high-tech instrumentation. The first wave was found to have a wavelength of 3 x 10 m and the second wave had a wavelength of 3 x 10 m. Which wave would have a higher frequency? Explain​

Answer 1

Step-by-step explanation:

The first wave was found to have a wavelength of 3 x 10⁵ m and the second wave had a wavelength of 3 x 10⁴ m

We need to find which wave have a higher frequency.

The relation between frequency and wavelength is given by :

`c=f\lambda`

Let f₁ and f₂ be the frequency of wave 1 and wave 2.

`f_1=(c)/(\lambda_1)\\\\f_1=(3* 10^8)/(3* 10^5)\\\\=1000\ Hz`

And

`f_2=(c)/(\lambda_2)\\\\f_2=(3* 10^8)/(3* 10^4)\\\\=10000\ Hz`

Hence, the wave having less wavelength will have higher frequency. The wave having wavelength 3 x 10⁴ m will have higher frequency.