11.2k views
5 votes
A fly has two alleles for the color of its eyes. The green allele is recessive, and

is represented by q. The blue allele is dominant, and is represented by p. If 44
of 100 organisms are green, what is p?
Homozygous dominant+ Heterozygous + Homozygous recessive = 1
↓↓↓
p²+ 2pq+q=1
A. 0.66
B. 0.56
C. 0.44
D. 0.34

User Mox Shah
by
3.9k points

1 Answer

4 votes

Answer: D. 0.34

Step-by-step explanation:


Hardy-Weinberg Principle

The Hardy-Weinberg Principle is a theory in biology that represents populations of organisms that don't experience any changes in genotypic frequency from generation to generation. These populations must meet the following conditions:

  • No genetic mutations
  • Completely random mating
  • No gene flow
  • No selection (natural or artificial)
  • An infinite population size

If a population meets these criteria, its genetic and allelic frequencies will remain constant and the population will be in Hardy-Weinberg Equilibrium. However, it is not possible for this to occur in nature, because at least one condition will always be violated in natural populations.

Hardy-Weinberg Equations

There are two important equations to use when doing problems like this. The first is p + q = 1. It represents the allelic frequency of the population.

  • p = the frequency of the dominant allele
  • q = the frequency of the recessive allele


The second equation is p² + 2pq + q² = 1, which shows the predicted frequencies of the three possible genotypes.

  • = the genotype frequency of homozygous dominants
  • 2pq = the genotype frequency of heterozygotes
  • = the genotype frequency of homozygous recessives

Our Fly Problem

44 of our 100 organisms are green, and we know that to be green, they must have a homozygous recessive genotype (gg). That means that the frequency of homozygous recessives (q²) = 44/100 or 0.44. Since we have q², we can just take the square root to find q.


√(q^2)=
√(0.44)

q = 0.66

Now, we can plug q into our first equation, p + q = 1.

p + 0.663 = 1

p = 0.337, or about 0.34

To make sure these are right, we can plug them into the Hardy-Weinberg equation to check!

p² + 2pq + q² = 1

(0.34)² + 2(0.34)(0.66) + (0.66)² = 1

0.1156 + 0.4488 + 0.4356 = 1

1 = 1

User Nightfire
by
3.7k points