Question

Help me pleaseee (10 points)

Answer 1

Answer: approximately 582 feet.

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Work Shown:

Let

x = length of AD in feet

y = length of DC in feet

x and y are positive real numbers.

For now, focus on triangle BCD. Ignore point A and its associated angle.

tan(angle) = opposite/adjacent

tan(D) = BC/DC

tan(16) = 125/y

y*tan(16) = 125

y = 125/tan(16)

y = 435.926805480113

y = 435.926805

The value of y is approximate

Now focus on triangle ABC. Ignore point D and its associated angle.

tan(angle) = opposite/adjacent

tan(A) = BC/AC

tan(A) = BC/(AD+DC)

tan(7) = 125/(x + y)

(x+y)*tan(7) = 125

x*tan(7) + y*tan(7) = 125

x*tan(7) = 125 - y*tan(7)

x = ( 125-y*tan(7) )/( tan(7) )

x = ( 125-435.926805*tan(7) )/( tan(7) )

x = 582.116498496824

x = 582

The distance from A to D is approximately 582 feet.

Answer 2

Explanation:

tan(16)=125/a

tan(16)=35.8 (DC)

tan(7)=125/a

tan(7)=15.3

35.8-15.3=20.5

Sorry if that's incorrect, my best is 20.5 feet.