Final answer:
The condition of a line lined up with 2x + y = 1 and going through the point (- 2, 2) is y = - 2x - 2, as equal lines share a similar slant, which is - 2 for this situation.
Step-by-step explanation:
To find the condition of the line that is lined up with 2x + y = 1 and goes through the point (- 2, 2), we first need to decide the slant of the given line. We can change over the given condition into the slant catch structure, y = mx + b, where m addresses the incline, and b is the y-capture. To do this, segregate y by taking away 2x from the two sides:
y = - 2x + 1
Presently we see that the slant m is - 2. Since equal lines have a similar slant, the new line will likewise have a slant of - 2. Then, we utilize the slant catch structure and plug in the slant m and the directions of the given highlight address for b:
2 = - 2(- 2) + b
2 = 4 + b
b = 2 - 4
b = - 2
Consequently, the condition of our equal line is y = - 2x - 2.