162k views
0 votes
What is an equation of the line that passes through the point (-2, 2) and is parallel to the line 2x + y = 1?​

User Lowndrul
by
7.7k points

1 Answer

5 votes

Final answer:

The condition of a line lined up with 2x + y = 1 and going through the point (- 2, 2) is y = - 2x - 2, as equal lines share a similar slant, which is - 2 for this situation.

Step-by-step explanation:

To find the condition of the line that is lined up with 2x + y = 1 and goes through the point (- 2, 2), we first need to decide the slant of the given line. We can change over the given condition into the slant catch structure, y = mx + b, where m addresses the incline, and b is the y-capture. To do this, segregate y by taking away 2x from the two sides:

y = - 2x + 1

Presently we see that the slant m is - 2. Since equal lines have a similar slant, the new line will likewise have a slant of - 2. Then, we utilize the slant catch structure and plug in the slant m and the directions of the given highlight address for b:

2 = - 2(- 2) + b

2 = 4 + b

b = 2 - 4

b = - 2

Consequently, the condition of our equal line is y = - 2x - 2.

User Pour
by
7.7k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories