Question

In triangle ABC, what is the measure of angle Cif A = 85°, a = 35, and c = 25?

Answer 1

To find the measure of angle C, you can use the Law of Cosines.

25^2 = 35^2 + 85^2 - 2*35*85*cos(C)

cos(C) = (35^2 + 85^2 - 25^2) / (2*35*85)

C = arccos((35^2 + 85^2 - 25^2) / (2*35*85))

Step-by-step explanation:

To find the measure of angle C in triangle ABC, we can use the Law of Cosines. The formula for the Law of Cosines is c^2 = a^2 + b^2 - 2ab*cos(C), where a and b are the lengths of the sides opposite to angles A and B, and c is the length of the side opposite to angle C. Plugging in the given values, we have:

25^2 = 35^2 + 85^2 - 2*35*85*cos(C)

Simplifying and solving for C, we get:

cos(C) = (35^2 + 85^2 - 25^2) / (2*35*85)

C = arccos((35^2 + 85^2 - 25^2) / (2*35*85))