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Please Help, I am stuck on this question.

Please Help, I am stuck on this question.-example-1
User Adit
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1 Answer

5 votes

Answer:

(15/17 = sin ∠ JLK)

(first option listed)

Step-by-step explanation:

the "sin ∠ JLK" is what we can simply think of as the inside measurement of angle/corner L. (L is the letter in the middle of ∠ JLK , and if you imagine drawing a line from J to L to K, you would see that the only angle you formed both sides of is corner L)

so, we are looking for the sin of L.

(SOH CAH TOA)

we know that

sin = opposite / hypotenuse

However, we do not have the opposite value of this triangle yet.

-----

we can solve the length of the opposite side with the Pythagorean theorem:

a² + b² = c²

8² + b² = 17²

64 + b² = 289

- 64 - 64

b² = 225

√b² = √225

b = 15

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so, to solve for sin L,

(sin = opposite / hypotenuse)

we should divide the opposite (15) over the hypotenuse (17)

so, 15 / 17 = sin L

(15/17 = sin ∠ JLK)

User David McGraw
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