9.9k views
3 votes
Which ordered pairs are solutions to the inequality 3x-4y>5

User Weir
by
4.1k points

1 Answer

4 votes

Note: you did not provide the answer options, so I am, in general, solving this query to solve your concept, which anyways would clear your concept.

Answer:

Please check the explanation.

Explanation:

Given the inequality


3x-4y>5

All we need is to find any random value of 'x' and then solve the inequality.

For example, putting x=3


3\left(3\right)-4y>5


9-4y>5


-4y>-4


\mathrm{Multiply\:both\:sides\:by\:-1\:\left(reverse\:the\:inequality\right)}


\left(-4y\right)\left(-1\right)<\left(-4\right)\left(-1\right)


4y<4


\mathrm{Divide\:both\:sides\:by\:}4


(4y)/(4)<(4)/(4)


y<1

So, at x = 3, the calculation shows that the value of y must be less

than 1 i.e. y<1 in order to be the solution.

Let us take the random y value that is less than 1.

As y=0.9 < 1

so putting y=0.9 in the inequality


3\left(3\right)-4\left(0.9\right)


=9-3.6


=5.4

  • As 5.4 > 5

Means at x=3, and y=0.9, the inequality is satisfied.

Thus, (3, 0.9) is one of the many ordered pairs solutions to the inequality 3x-4y>5.

User Yang Bo
by
5.0k points