215k views
3 votes
12х - 5 >3х^2 +5
I am confused how to solve this.

1 Answer

5 votes

Answer (3 different forms):

1st Form:


2+-(1)/(3) √(6) <x<2+(1)/(3) √(6)

2nd Form:


-\sqrt(2)/(3)+2<x<\sqrt(2)/(3)+2

3rd Form:


(6-√(6))/(3)<x< (6+√(6))/(3)

Or


((6-√(6))/(3)),((6+√(6))/(3))

Explanation:

You can see that I put three different forms of answers, but they are all still equivalent answers. The reason why I got three different answers is because I put the inequality in three different calculators and they all got me different answers, but all three are still equivalent. The following three attachments are images of the three calculators that I used to solve.

Hope this helps and answers your question! :)

12х - 5 >3х^2 +5 I am confused how to solve this.-example-1
12х - 5 >3х^2 +5 I am confused how to solve this.-example-2
12х - 5 >3х^2 +5 I am confused how to solve this.-example-3
User Jurjen
by
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