A parallel circuit is shown in the diagram above. In this case the current supplied by the battery splits up, and the amount going through each resistor depends on the resistance. If the values of the three resistors are: R1 = 82, R2=82, and R3 = 42, the total resistance is found by: 1/R = 1/8+1/8+ 1/4 = 1/2. This gives R = 22. With a 10 V battery, by V = 1 R the total current in the circuit is: I = V/R = 10/2 = 5 A. The individual currents can also be found using I = V/R. The voltage across each resistor is 10 V, so the resistance across R1 : 2.5A 1.25V 2.5V 1.25A