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Use technology to find the​ P-value for the hypothesis test described below. The claim is that for a smartphone​ carrier's data speeds at​ airports, the mean is μ=11.00 Mbps. The sample size is n=14 and the test statistic is t=1.484. ​P-value=nothing ​(Round to three decimal places as​ needed.)

User Jvecsei
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Solution :

The null and alternative hypothesis is given by


$H_0: \mu = 11$


$H_a: \mu \\e 11$

Assume that the level of significance, α = 0.05

The t-test statistics is, t = 1.484

Degree of freedom :

df = n - 1

= 14 - 1

= 13

The P-value is given by

P-value = 2P (T>|t|)

= 2P(T>|1.484|)

= 2P(T>1.484)

= 2(=T.DIST.RT(1.484,13))

= 0.05

User Dennis Doomen
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