Answer:
The value of μ will be "0.82".
Explanation:
The given question is incomplete. Please find attachment of the complete question below.
The given three random samples are 0.8, 0.95 and 0.7.
Now,
⇒
![\mu=\frac{\bar{x_1}+\bar{x_2}+\bar{x_3}}{3}](https://img.qammunity.org/2021/formulas/mathematics/college/g4gbhihe20lfcj6733f66apetotvdm2mm6.png)
On substituting the estimated values, we get
⇒
![=(0.8+0.95+0.7)/(3)](https://img.qammunity.org/2021/formulas/mathematics/college/a4awerouysenyduvuvv0hc1plgmxc4hpds.png)
⇒
![=(2.45)/(3)](https://img.qammunity.org/2021/formulas/mathematics/college/bc1h7q6f7tj4gycbk4rbxkn7ejgrzp9ie0.png)
⇒
![=0.82](https://img.qammunity.org/2021/formulas/mathematics/college/zcb8be28czwr1eih6q7rdjbpgkqk1fr8fs.png)
It will not rational here, considering the equivalent significance, since the sampling amount for sample 3 becomes somewhat big 200.