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What is the line that has a slope of -2/3 and passes through point -3,-1?

2 Answers

8 votes

Answer:

y = (- 2/3)x - 3

Explanation:

y = mx + c

y = (- 2/3)x + c

Now let's substitute the values (-3,-1)

- 1 = (- 2/3)(-3) + c

-1 = 2 + c

c = - 3

Therefore,

y = (-2/3)x - 3

User Ctrlbrk
by
8.1k points
8 votes

Answer:

y = -2/3x - 3

Explanation:

y = mx + b

y = y coordinate → given: - 1

m = slope → given: - 2/3

x = x coordinate → given: - 3

b = y intercept → need to find

y = -2/3x + b → -1 = -2/3(-3) + b

-1 = 2 + b

subtract 2 from both sides

-1 - 2 = 2 - 2 + b

-3 = b

y = -2/3x - 3

User Ivan Smetanin
by
8.5k points

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