Question

During the contraction of the heart, 65 cm3 blood is ejected from the left ventricle into the aorta with a velocity of approximately 103 cm/s. The blood volume traverses the aortic arch, exiting with the same speed but opposite direction. Assume the mass density of the blood is 1060 kg/m3 blood, the aortic arch remains stationary, and that the heart rate is 59 bpm. What is the average force exerted by the blood on the wall of the aorta.

Answer 1

The value
`F  =  0.1396 \ N`

Step-by-step explanation:

From the question we are told that

The volume blood ejected is
`V = 65 \ cm^3 = 65*10^(-6) \ m^3`

The velocity of the blood ejected is
`v = 103 \ cm/s = (103)/(100) = 1.03 \ m/s`

The density of blood is
`\rho = 1060 \ kg/m^3`

The heart beat is
`R = 59 \ bpm(beats \ per \ minute) = (59)/(60)= 0.9833\ bps`

The average force exerted by the blood on the wall of the aorta is mathematically represented as

`F = 2 * \rho * V * R * v`

=>
`F  =  2 * 1060  *  65*10^(-6)  *  0.9833 *  1.03`

=>
`F  =  0.1396 \ N`