Question

Car 2 passes car 1. To a stationary observer, car 1 has a velocity of 28 m/s to the east and car 2 has a velocity of 33 m/s to the east. How much time will pass before car 2 is 14 m ahead of car 1?

Answer 1

2.8 s

Explanation:

33x = 28x + 14(m)

5x = 14(m)

x = 2.8(s)