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Car 2 passes car 1. To a stationary observer, car 1 has a velocity of 28 m/s to the east and car 2 has a velocity of 33 m/s to the east. How much time will pass before car 2 is 14 m ahead of car 1?
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Car 2 passes car 1. To a stationary observer, car 1 has a velocity of 28 m/s to the east and car 2 has a velocity of 33 m/s to the east. How much time will pass before car 2 is 14 m ahead of car 1?

User Bhavin Patel
by
7.6k points

1 Answer

12 votes

Answer:

2.8 s

Explanation:

33x = 28x + 14(m)

5x = 14(m)

x = 2.8(s)

User Tisuchi
by
7.9k points
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