Answer:
To raise the mass to an altitude of 12,000 Km 2E joules are required.
Step-by-step explanation:
Gravitational Potential Energy
It's the energy stored in an object because of its vertical position or height in a gravitational field.
It can be calculated with the equation:
U=m.g.h
Where:
m = mass of the object
h = height with respect to a fixed reference
g = acceleration of gravity, or
.
If a mass has a height h1, its potential energy is
![U_1=m.g.h_1](https://img.qammunity.org/2021/formulas/physics/high-school/iya1892w4t8v3sm0r8abc8efzz35ty2gty.png)
If a mass has a height h2, its potential energy is
![U_2=m.g.h_2](https://img.qammunity.org/2021/formulas/physics/high-school/pmdfmnfn12yqxfr96ltqdfvgeu2uyjbwp5.png)
The ratio of both potential energies is:
![\displaystyle (U_2)/(U_1)=(m.g.h_2)/(m.g.h_1)](https://img.qammunity.org/2021/formulas/physics/high-school/hhp6wqtwvt09t0gcb05sxt9u4jm1ndeku5.png)
Simplifying:
![\displaystyle (U_2)/(U_1)=(h_2)/(h_1)](https://img.qammunity.org/2021/formulas/physics/high-school/vutmbawljb5mt43659o2g2pwij2zda2r19.png)
Solving for U2:
![\displaystyle U_2=U_1.(h_2)/(h_1)](https://img.qammunity.org/2021/formulas/physics/high-school/ga5tvu0vgkbilb2hpix9e1sbb4ox1e4u94.png)
Since U1=E:
![\displaystyle U_2=E.(12,000~Km)/(6,000~Km)](https://img.qammunity.org/2021/formulas/physics/high-school/utiepl79gmpdqcq3hvj2b3v4sdzqc7lp4g.png)
![U_2 = 2E](https://img.qammunity.org/2021/formulas/physics/high-school/cbvp8m8omlbkiux0adozn6ppl39r5bblqp.png)
To raise the mass to an altitude of 12,000 Km 2E joules are required.