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Cot? 2x + cos2x + sin’ 2x = csc? 2x
Need help with 40

Cot? 2x + cos2x + sin’ 2x = csc? 2x Need help with 40-example-1

1 Answer

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Answer:


\rule{100mm}{0.1mm}


\cot^2(2x)+\cos^2(2x)+\sin^2(2x)=\csc^2(2x)


(\cos^2(2x))/(\sin^2(2x)) +[(\cos^2(2x)+\sin^2(2x)]=\csc^2(2x)


(\cos^2(2x))/(\sin^2(2x)) +1=\csc^2(2x)


(\cos^2(2x)+\sin^2(2x))/(\sin^2(2x))=\csc^2(2x)


(1)/(sin^2(2x)) =\csc^2(2x)


\boxed{\csc^2(2x)=\csc^2(2x)}


\rule{100mm}{0.1mm}

User Richard Purdie
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