Question

Find 3 consecutive odd integers such that 10 times the first is 59 more than the third

Answer 1

9514 1404 393

Answer:

7, 9, 11

Explanation:

Let x represent the middle integer. Then the first is x-2, and the third is x+2. The given relation is ...

10(x -2) = 59 +(x +2)

10x -20 = x +61 . . . . eliminate parentheses

9x = 81 . . . . . . . . . . . add 20-x

x = 9 . . . . . . . . . . . . . divide by 9

The integers are 7, 9, 11.

_____

Check

7·10 = 11 +59 . . . true