Question

A box has a momentum of

38.0 kg*m/s to the right. A 88.3 N
force pushes it to the right for 0.338
S. What is the final momentum of
the box?

Answer 1

67.9 kg*m/s

Step-by-step explanation:

Pi = 38 kgm/s

F = 88.3N and ∆t = 0.338s

Final momentum Pf = Pi + F∆t = 38 + (88.3)(0.338) = 38 + 29.8454

=) Pf = 67.8454 kgm/s = 67.85kg*m/s

Your answer is 67.9kg*m/s with three significant figures

hope this helps your troubles!