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A 7.2 L balloon at 2 atm of pressure has its pressure reduced to 0.5 atm. What is the new size of the balloon, in liters?

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Step-by-step explanation:

using Boyles law: which shows the relationship between pressure and volume, when temperature Is kept constant

P1V1 = P2V2

2 x 7.2 = 0.5 x V2

14.4 = 0.5 x V2

V2 = 14.4/0.5 = 28.8 L

Hence the new size of the balloon in litres is 28.8

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