Question

The Grand Canyon Skywalk at Eagle Point is a horseshoe shaped steel frame with a glass floor looking down to the Grand Canyon below. The Skywalk extends 70 feet over the canyon rim and is 10 feet wide. The walkway consists of a semicircle with a straight portion on each side as indicated in the diagram below. How many square feet of glass are needed to cover the Skywalk floor? (Round your final answer to 1 decimal place and any intermediate calculations to 2 decimal places. Be sure to include units.)

Answer 1

Answer: It will be needed 864 square feet of glass to cover the Skywalk floor.

Explanation: The figure below shows the area in question.

Area of a circle is given by

`A=\pi.r^(2)`

The walkway is a semicircle. Then, area will be:

`A=(\pi.r^(2))/(2)`

The area that will be covered with glass is the area between the outer and the inner circles. So, area is

`A_(t)=A_(outer)-A_(inner)`

`A_(t)=(\pi.r_(o)^(2))/(2)- (\pi.r_(i)^(2))/(2)`

`A_(t)=(\pi)/(2)(32.5^(2)-22.5^(2))`

`A_(t)=(\pi)/(2)(550)`

`A_(t)=` 864

To cover the Skywalk floor is needed 864
`ft^(2)` of glass.