Question

A car traveling initially at 7.35 m/s acceler-

ates at the rate of 0.824 m/s² for 2.09 s.
What is its velocity at the end of the accel-
eration?
Answer in units of m/s.

Answer 1

`v_f=9,07~m/s`

Step-by-step explanation:

Constant Acceleration Motion

It's a type of motion in which the velocity of an object changes uniformly in time.

Being a the constant acceleration, vo the initial speed, vf the final speed, and t the time, the following relation applies:

`v_f=v_o+at`

The car initially travels at vo=7.35 m/s and accelerates at a rate of
`a=0.824~m/s^2` during t=2.09 s.

The final velocity is:

`v_f=7.35+0.824*2.09`

`\mathbf{v_f=9,07~m/s}`