Question

When 21.5 g of CH4 gas reacts with 387.5 g O2 gas, how much CO2 is formed?

Answer 1

Mass = 58.96 g

Step-by-step explanation:

Given data:

Mass of CH₄ = 21.5 g

Mass of O₂ = 387.5 g

Mass of CO₂ formed = ?

Solution:

Chemical equation:

CH₄ + 2O₂ → CO₂ + 2H₂O

Number of moles of CH₄:

Number of moles = mass / molar mass

Number of moles = 21.5 g/ 16 g/mol

Number of moles = 1.34 mol

Number of moles of O₂ :

Number of moles = mass / molar mass

Number of moles = 387.5 g/ 32 g/mol

Number of moles = 12.1 mol

now we will compare the moles of CO₂ with O₂ and CH₄.

O₂ : CO₂

2 : 1

12.1 : 1/2×12.1 = 6.05 mol

CH₄ : CO₂

1 : 1

1.34 : 1.34

Number of moles of CO₂ produced by CH₄ are less thus it will limiting reactant.

Mass of CO₂:

Mass = number of moles × molar mass

Mass = 1.34 mol × 44 g/mol

Mass = 58.96 g