Question

What is the empirical formula of a molecule containing 24% carbon (C), 6%

hydrogen (H), and 70% chlorine (CI)?
O A. CH3C1
B. C2H6Cl2
C. C24H6C170
O D. CHCI
SUBMIT

Answer 1

CH3Cl

Step-by-step explanation:

a-p-e-x

Answer 2

Empirical formula is CH₃Cl.

Step-by-step explanation:

Given data:

Percentage of hydrogen = 6%

Percentage of carbon = 24%

Percentage of chlorine= 70%

Empirical formula = ?

Solution:

Number of gram atoms of H = 6/ 1 = 6

Number of gram atoms of C = 24 /12= 2

Number of gram atoms of Cl = 70/ 35.45 = 2

Atomic ratio:

C : H : Cl

2/2 : 6/2 : 2/2

1 : 3 : 1

C : H : Cl = 1 : 3 : 1

Empirical formula is CH₃Cl.