Question

Solve the following equation algebraically:

-16 = 16x^2 How many solutions does this equation have? Explain.
a. -1=x^2: One solution because only -1 will satisfy the equation.
b. -1=x^2: No real solution because there is no real number that, when squared, produces -1.
C. 1=x^2: Two solutions because the square root of 1 is positive 1 and negative 1.
d. 1=-x^2: One solution because only -1 will satisfy the equation.​

Answer 1

B. -1 = x^2; No real solution because there is no real number that, when squared, produces -1

Explanation:

Answer 2

1=x²: two solutions because the square root of 1 is positive 1 and negative 1